Oblicz

[kapa4343]

\(\left( 15 \frac{2}{3}-7 \frac{1}{2} \right):1 \frac{1}{2}\)
\(2* \left( \frac{1}{3} \right)2+3* \left( \frac{1}{2} \right)3\)
\(4 \frac{1}{2}*1 \frac{1}{3} -2 \frac{2}{5}* \frac{5}{7}\)
\(1 \frac{2}{3}- \frac{5}{6} +2 \frac{1}{10}:1 \frac{6}{15}\)
\(\left( \frac{5}{8} + \frac{1}{2} \right):1 \frac{1}{2}- \frac{1}{3}\)


To znaczy do kwadratu
\(\left( \frac{1}{3} \right)2\)
\(\left( \frac{1}{2} \right)3\)

[irena]

1.
a)
\(=(15\frac{4}{6}-7\frac{3}{6}):1\frac{1}{2}=8\frac{1}{6}:1\frac{1}{2}=\frac{49}{6}:\frac{3}{2}=\frac{49}{6}\cdot\frac{2}{3}=\frac{49}{9}=5\frac{4}{9}\)

[irena]

b)
\(=2\cdot\frac{1}{9}+3\cdot\frac{1}{4}=\frac{2}{9}+\frac{3}{4}=\frac{8+27}{36}=\frac{35}{36}\)

[irena]

c)
\(=\frac{9}{2}\cdot\frac{4}{3}-\frac{12}{5}\cdot\frac{5}{7}=6-\frac{12}{7}=6-1\frac{5}{7}=4\frac{2}{7}\)

[irena]

d)
\(=1\frac{4}{6}-\frac{5}{6}+\frac{21}{10}:\frac{21}{15}=\frac{5}{6}+\frac{21}{10}\cdot\frac{15}{21}=\frac{5}{6}+\frac{3}{2}=\frac{5}{6}+\frac{9}{6}=\frac{14}{6}=2\frac{2}{6}=2\frac{2}{3}\)

[irena]

2.
\((\frac{1}{3})^2=\frac{1^2}{3^2}=\frac{1}{9}\)

\((\frac{1}{2})^3=\frac{1^3}{2^3}=\frac{1}{8}\)

[marcin77]

1.
e)
\(\left( \frac{5}{8} + \frac{1}{2} \right):1 \frac{1}{2}- \frac{1}{3}=( \frac{5}{8}+ \frac{4}{8} ) \cdot \frac{2}{3}- \frac{1}{3}= \frac{9}{8} \cdot \frac{2}{3}-\frac{1}{3}= \frac{3}{4}- \frac{1}{3}= \frac{9-4}{12}= \frac{5}{12}\)