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Granica ciągu
: 26 gru 2014, 13:59
autor: majlo93
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\(\Lim_{n\to \infty } \frac{n^3 +2n^2 + 1}{n-3n^3}\)
: 26 gru 2014, 14:31
autor: denatlu
\(\Lim_{n\to \infty } \frac{n^3 +2n^2 + 1}{n-3n^3}= \Lim_{n\to \infty } \frac{n^3(1+\frac{2}{n}+\frac{1}{n^3})}{n^3(\frac{1}{n^2}-3)}=\Lim_{n\to \infty } \frac{1+\frac{2}{n}+\frac{1}{n^3}}{\frac{1}{n^2}-3}=-\frac{1}{3}\)