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logarytmy
: 28 sty 2023, 15:51
autor: BarT123oks
Niech \(k=\log_{21}7\). Wyznacz \(\log_{7}27\)
Re: logarytmy
: 28 sty 2023, 16:39
autor: radagast
\(\log_{7}27= \frac{\log_{21}27}{\log_{21}7}=\frac{\log_{21}3^3}{\log_{21}7}=\frac{3\log_{21}3}{\log_{21}7}=\frac{3\log_{21} \frac{21}{7} }{\log_{21}7}=\frac{3\log_{21}21- 3\log_{21}7 }{\log_{21}7}= \frac{3-3k}{k} \)