Oblicz przez czesci calke nieoznaczona
: 05 lip 2020, 10:57
\(∫(-4x+4)sin(4x-9)dx\) prosze o pomoc z gory dziekuje
\(\displaystyle \int(-4x+4)\sin(4x-9)dx= \\
\displaystyle \int(-4x+4) \left(- \frac{1}{4} \cos(4x-9) \right) 'dx= \\
\displaystyle \int(x-1) \left(\cos(4x-9) \right) 'dx=\\
\displaystyle (x-1)\cos(4x-9) -\int(x-1) ' \cos(4x-9) dx = \\
\displaystyle (x-1)\cos(4x-9) -\int\cos(4x-9) dx = \\
\displaystyle (x-1)\cos(4x-9) - \frac{1}{4} \sin(4x-9) +C \\
\)