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całka

: 21 cze 2017, 10:30
autor: kate84
\(\int \frac{dx}{cos2x}\)

: 21 cze 2017, 11:20
autor: eresh
\(\int\frac{1}{\cos 2x}dx=\int\frac{\sin^22x+\cos^22x}{\cos 2x}dx=\int\frac{\sin^22x}{\cos 2x}dx+\int\cos 2xdx\)