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Oblicz

: 10 mar 2016, 16:19
autor: BladyWZ
Bardzo prosze o pomoc
z góry dziękuje :wink:
zad.1

\(3ab - \frac{5a}{3b}\) dla \(a=4\)\(,b= \frac{1}{2}\)


zad.2

a). \(-7 \frac{1}{8} -3 \frac{5}{6} : (-7 \frac{1}{5})\)
b). \((7- \frac{1}{3} )(7+5) - \frac{3}{3} : \frac{5}{4}\)

Re: Oblicz

: 10 mar 2016, 16:28
autor: eresh
BladyWZ pisze:Bardzo prosze o pomoc
z góry dziękuje :wink:
zad.1

\(3ab - \frac{5a}{3b}\) dla \(a=4\)\(,b= \frac{1}{2}\)
\(3\cdot 4\cdot \frac{1}{2}-\frac{5\cdot 4}{3\cdot 0,5}=6-\frac{20}{\frac{3}{2}}=6-20\cdot\frac{2}{3}=6-\frac{40}{3}=-\frac{22}{3}\)

Re: Oblicz

: 10 mar 2016, 16:40
autor: eresh
BladyWZ pisze: zad.2

a). \(-7 \frac{1}{8} -3 \frac{5}{6} : (-7 \frac{1}{5})\)

\(-7\frac{1}{8}-3\frac{5}{6}:(-7\frac{1}{5})=-7\frac{1}{8}-\frac{23}{6}\cdot (-\frac{5}{36})=-\frac{57}{8}+\frac{115}{216}=\frac{-1539}{216}+\frac{115}{216}=\frac{-1424}{216}=-\frac{178}{27}=-6\frac{16}{27}\)

Re: Oblicz

: 10 mar 2016, 16:43
autor: eresh
BladyWZ pisze:
zad.2

b). \((7- \frac{1}{3} )(7+5) - \frac{3}{3} : \frac{5}{4}\)[/color]
\((7- \frac{1}{3} )(7+5) - \frac{3}{3} : \frac{5}{4}=6\frac{2}{3}\cdot 12-1\cdot\frac{4}{5}=\frac{20}{3}\cdot 12-\frac{4}{5}=80-\frac{4}{5}=79\frac{1}{5}\)