algebra
: 15 paź 2009, 18:08
Find the number that when divided by 3 gives the rest 2
and divided by 4 gives rest 0
and divided by 7 gives rest 1.
I solved as follows:
p1 = 3 q1 = 2
p2 = 4 q2 = 0
p3 = 7 q3 = 1
3 | (q-2) = 3a + 2
4 | (q-0) = 4b + 0
7 | (q-1) = 7c + 1
what are the results for the numbers a, b, c and what is the q?
and divided by 4 gives rest 0
and divided by 7 gives rest 1.
I solved as follows:
p1 = 3 q1 = 2
p2 = 4 q2 = 0
p3 = 7 q3 = 1
3 | (q-2) = 3a + 2
4 | (q-0) = 4b + 0
7 | (q-1) = 7c + 1
what are the results for the numbers a, b, c and what is the q?