Strona 1 z 1

logarytmy

: 22 mar 2011, 15:42
autor: evelinkaxp
\(\log_93\)
\(\log_{\frac{1}{4}}16\)
\(\log_{25}\(\frac{1}{5}\)\)
\(\log_24\)

: 22 mar 2011, 16:01
autor: octahedron
\(\log_93=\log_99^{\frac{1}{2}}=\frac{1}{2}\)
\(\log_{\frac{1}{4}}16=\log_{\frac{1}{4}}4^2=\log_{\frac{1}{4}}\({1\over 4}\)^{-2}=-2\)
\(\log_{25}\(\frac{1}{5}\)=\log_{25}\(5\)^{-1}=\log_{25}\(25\)^{-{1\over 2}}=-\frac{1}{2}\)
\(\log_24=\log_22^2=2\)