uklad rownan

[natusia]

zadanie.1

a) \(\begin{cases} x=2x+3y-1\\5=x+4y \end{cases}\)

b) \(\begin{cases} x+6=3x+y \\ 4=x-2y+5\end{cases}\)

Proszę o pomoc !

[heja]

a)\(\begin{cases}x+3y-1=0\\ x+4y-5=0 \end{cases}\)
od równania (2) odejmujemy (1)i mamy:
\(y-4=0 \to y=4 \to x=1-12=-11\)
odp.(x;y)=(-11;4)

[heja]

b)\(\begin{cases} 2x+y-6=0 / \cdot 2\\ x-2y+1=0\end{cases}\)

\(\begin{cases} 4x+2y-12=0\\ x-2y+1=0\end{cases}\)
dodajemy równania stronami i mamy:
\(5x-11=0 \to x= \frac{11}{5} \to y=6-2 \cdot \frac{11}{5}= \frac{8}{5}\)
odp.\((x;y)=( \frac{11}{5}; \frac{8}{5})\)