Rozwiąż równanie

[julka1]

\(x^{4}-3x=3x^{2}-x^3\)

[wsl1993_]

\(x^{4}-3x=3x^{2}-x^3
x^4+x^3-3x^2-3x=
x^3(x+1)-3x(x+1)=
(x+1)(x^3-3x)=(x+1)x(x^2-3)=
x(x+1)(x-\sqrt3)(x+\sqrt3) \Rightarrow
x=0 \vee x=-1 \vee x=\sqrt3 \vee x=-\sqrt3\)

[jola]

\(x^4+x^3-3x^2-3x=0\\x^3(x+1)-3x(x+1)=0\\x(x+1)(x^2-3)=0\\x(x+1)(x- \sqrt{3})(x+ \sqrt{3} =0\\ x=0\ \ lub\ \ x=-1\ \ lub\ \ x= \sqrt{3} \ \ \ lub\ \ x=- \sqrt{3}\)