Forum serwisu

Find the number that when divided by 3 gives the rest 2 and divided by 4 gives rest 0 and divided by 7 gives rest 1. I solved as follows: p1 = 3 q1 = 2 p2 = 4 q2 = 0 p3 = 7 q3 = 1 3 | (q-2) = 3a + 2 4 | (q-0) = 4b + 0 7 | (q-1) = 7c + 1 what are the results for the numbers a, b, c and what is the q?